2/5(x+3)=1/2(x-5)

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Solution for 2/5(x+3)=1/2(x-5) equation: 



2/5(x+3)=1/2(x-5)

We move all terms to the left:

2/5(x+3)-(1/2(x-5))=0



Domain of the equation: 5(x+3)!=0

x∈R





Domain of the equation: 2(x-5))!=0

x∈R



We calculate fractions


(4xx/(5(x+3)*2(x-5)))+(-5xx/(5(x+3)*2(x-5)))=0



We calculate terms in parentheses: +(4xx/(5(x+3)*2(x-5))), so:

4xx/(5(x+3)*2(x-5))

We multiply all the terms by the denominator


4xx

Back to the equation:

+(4xx)





We calculate terms in parentheses: +(-5xx/(5(x+3)*2(x-5))), so:

-5xx/(5(x+3)*2(x-5))

We multiply all the terms by the denominator


-5xx

Back to the equation:

+(-5xx)



We get rid of parentheses

4xx-5xx=0

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