6(3n+1)-4n=-2(n-5)

Solution for 6(3n+1)-4n=-2(n-5) equation:

6(3n+1)-4n=-2(n-5)

We move all terms to the left:

6(3n+1)-4n-(-2(n-5))=0

We add all the numbers together, and all the variables

-4n+6(3n+1)-(-2(n-5))=0

We multiply parentheses

-4n+18n-(-2(n-5))+6=0


We calculate terms in parentheses: -(-2(n-5)), so:

-2(n-5)

We multiply parentheses

-2n+10

Back to the equation:

-(-2n+10)


We add all the numbers together, and all the variables

14n-(-2n+10)+6=0

We get rid of parentheses

14n+2n-10+6=0

We add all the numbers together, and all the variables

16n-4=0

We move all terms containing n to the left, all other terms to the right

16n=4

n=4/16

n=1/4