2/5(j-3)=1/5(j-2)

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Solution for 2/5(j-3)=1/5(j-2) equation: 



2/5(j-3)=1/5(j-2)

We move all terms to the left:

2/5(j-3)-(1/5(j-2))=0



Domain of the equation: 5(j-3)!=0

j∈R





Domain of the equation: 5(j-2))!=0

j∈R



We calculate fractions


(10jj/(5(j-3)*5(j-2)))+(-5jj/(5(j-3)*5(j-2)))=0



We calculate terms in parentheses: +(10jj/(5(j-3)*5(j-2))), so:

10jj/(5(j-3)*5(j-2))

We multiply all the terms by the denominator


10jj

Back to the equation:

+(10jj)





We calculate terms in parentheses: +(-5jj/(5(j-3)*5(j-2))), so:

-5jj/(5(j-3)*5(j-2))

We multiply all the terms by the denominator


-5jj

Back to the equation:

+(-5jj)



We get rid of parentheses

10jj-5jj=0

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