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2/5c-5=-10-1/5c
We move all terms to the left:
2/5c-5-(-10-1/5c)=0
Domain of the equation: 5c!=0
c!=0/5
c!=0
c∈R
Domain of the equation: 5c)!=0We add all the numbers together, and all the variables
c!=0/1
c!=0
c∈R
2/5c-(-1/5c-10)-5=0
We get rid of parentheses
2/5c+1/5c+10-5=0
We multiply all the terms by the denominator
10*5c-5*5c+2+1=0
We add all the numbers together, and all the variables
10*5c-5*5c+3=0
Wy multiply elements
50c-25c+3=0
We add all the numbers together, and all the variables
25c+3=0
We move all terms containing c to the left, all other terms to the right
25c=-3
c=-3/25
c=-3/25
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