2/5(5x+20)=1/3(7x+6)

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Solution for 2/5(5x+20)=1/3(7x+6) equation: 



2/5(5x+20)=1/3(7x+6)

We move all terms to the left:

2/5(5x+20)-(1/3(7x+6))=0



Domain of the equation: 5(5x+20)!=0

x∈R





Domain of the equation: 3(7x+6))!=0

x∈R



We calculate fractions


(6x7/(5(5x+20)*3(7x+6)))+(-5x5/(5(5x+20)*3(7x+6)))=0



We calculate terms in parentheses: +(6x7/(5(5x+20)*3(7x+6))), so:

6x7/(5(5x+20)*3(7x+6))

We multiply all the terms by the denominator


6x7

We add all the numbers together, and all the variables

6x^7

We do not support expression: x^7

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