2z+6=3z+1*

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Solution for 2z+6=3z+1* equation: 



2z+6=3z+1*

We move all terms to the left:

2z+6-(3z+1*)=0

We add all the numbers together, and all the variables

2z-(+3z)+6=0

We get rid of parentheses

2z-3z+6=0

We add all the numbers together, and all the variables

-1z+6=0

We move all terms containing z to the left, all other terms to the right

-z=-6

z=-6/-1

z=+6

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