3x-2(4x+1)=19

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Solution for 3x-2(4x+1)=19 equation: 



3x-2(4x+1)=19

We move all terms to the left:

3x-2(4x+1)-(19)=0

We multiply parentheses

3x-8x-2-19=0

We add all the numbers together, and all the variables

-5x-21=0

We move all terms containing x to the left, all other terms to the right

-5x=21

x=21/-5

x=-4+1/5

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