2/5(10x-5)=2/3(9-6x)

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Solution for 2/5(10x-5)=2/3(9-6x) equation: 



2/5(10x-5)=2/3(9-6x)

We move all terms to the left:

2/5(10x-5)-(2/3(9-6x))=0



Domain of the equation: 5(10x-5)!=0

x∈R





Domain of the equation: 3(9-6x))!=0

x∈R



We add all the numbers together, and all the variables

2/5(10x-5)-(2/3(-6x+9))=0

We calculate fractions


(6x(-)/(5(10x-5)*3(-6x+9)))+(-10x1/(5(10x-5)*3(-6x+9)))=0



We calculate terms in parentheses: +(6x(-)/(5(10x-5)*3(-6x+9))), so:

6x(-)/(5(10x-5)*3(-6x+9))

We add all the numbers together, and all the variables

6x0/(5(10x-5)*3(-6x+9))

We multiply all the terms by the denominator


6x0

We add all the numbers together, and all the variables

6x

Back to the equation:

+(6x)





We calculate terms in parentheses: +(-10x1/(5(10x-5)*3(-6x+9))), so:

-10x1/(5(10x-5)*3(-6x+9))

We multiply all the terms by the denominator


-10x1

We add all the numbers together, and all the variables

-10x

Back to the equation:

+(-10x)



We get rid of parentheses

6x-10x=0

We add all the numbers together, and all the variables

-4x=0

x=0/-4

x=0

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