p(4p-1)=0

Solution for p(4p-1)=0 equation:

p(4p-1)=0

We multiply parentheses

4p^2-1p=0

a = 4; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·4·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*4}=\frac{0}{8}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*4}=\frac{2}{8}
=1/4
$