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2(x-3)+55=3(x-1)
We move all terms to the left:
2(x-3)+55-(3(x-1))=0
We multiply parentheses
2x-(3(x-1))-6+55=0
We calculate terms in parentheses: -(3(x-1)), so:We add all the numbers together, and all the variables
3(x-1)
We multiply parentheses
3x-3
Back to the equation:
-(3x-3)
2x-(3x-3)+49=0
We get rid of parentheses
2x-3x+3+49=0
We add all the numbers together, and all the variables
-1x+52=0
We move all terms containing x to the left, all other terms to the right
-x=-52
x=-52/-1
x=+52
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