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2/5(10x+25=-10-4(x+3)
We move all terms to the left:
2/5(10x+25-(-10-4(x+3))=0
Domain of the equation: 5(10x+25-(-10-4(x+3))!=0We multiply all the terms by the denominator
x∈R
2!=0
There is no solution for this equation
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