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5(x+1)3x-6(4x=3)
We move all terms to the left:
5(x+1)3x-6(4x-(3))=0
We multiply parentheses
15x^2+15x-24x+18=0
We add all the numbers together, and all the variables
15x^2-9x+18=0
a = 15; b = -9; c = +18;
Δ = b2-4ac
Δ = -92-4·15·18
Δ = -999
Delta is less than zero, so there is no solution for the equation
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