2(3c-2)=12c+6/2

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Solution for 2(3c-2)=12c+6/2 equation: 



2(3c-2)=12c+6/2

We move all terms to the left:

2(3c-2)-(12c+6/2)=0

We add all the numbers together, and all the variables

2(3c-2)-(12c+3)=0

We multiply parentheses

6c-(12c+3)-4=0

We get rid of parentheses

6c-12c-3-4=0

We add all the numbers together, and all the variables

-6c-7=0

We move all terms containing c to the left, all other terms to the right

-6c=7

c=7/-6

c=-1+1/6

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