1/9(27x-18)=6x-1/10(20+20x

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Solution for 1/9(27x-18)=6x-1/10(20+20x equation: 



1/9(27x-18)=6x-1/10(20+20x

We move all terms to the left:

1/9(27x-18)-(6x-1/10(20+20x)=0



Domain of the equation: 9(27x-18)!=0

x∈R





Domain of the equation: 10(20+20x)!=0

x∈R



We add all the numbers together, and all the variables

1/9(27x-18)-(6x-1/10(20x+20)=0

We calculate fractions


(10x2/(9(27x-18)*10(20x+20))+(-(6x-9x2)/(9(27x-18)*10(20x+20))=0



We calculate terms in parentheses: +(10x2/(9(27x-18)*10(20x+20))+(-(6x-9x2)/(9(27x-18)*10(20x+20)), so:

10x2/(9(27x-18)*10(20x+20))+(-(6x-9x2)/(9(27x-18)*10(20x+20)

We add all the numbers together, and all the variables

(-(+6x-9x^2)/(9(27x-18)*10(20x+20)+10x2/(9(27x-18)*10(20x+20))

We can not solve this equation

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