2(2c+4)+8=36

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Solution for 2(2c+4)+8=36 equation: 



2(2c+4)+8=36

We move all terms to the left:

2(2c+4)+8-(36)=0

We add all the numbers together, and all the variables

2(2c+4)-28=0

We multiply parentheses

4c+8-28=0

We add all the numbers together, and all the variables

4c-20=0

We move all terms containing c to the left, all other terms to the right

4c=20

c=20/4

c=5

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