2/5(10b-5)=-8

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Solution for 2/5(10b-5)=-8 equation: 



2/5(10b-5)=-8

We move all terms to the left:

2/5(10b-5)-(-8)=0



Domain of the equation: 5(10b-5)!=0

b∈R



We add all the numbers together, and all the variables

2/5(10b-5)+8=0

We multiply all the terms by the denominator


8*5(10b-5)+2=0

Wy multiply elements

40b(1+2=0

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