10(2y+2)-y=2(8y+8

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Solution for 10(2y+2)-y=2(8y+8 equation: 



10(2y+2)-y=2(8y+8

We move all terms to the left:

10(2y+2)-y-(2(8y+8)=0

We add all the numbers together, and all the variables

-1y+10(2y+2)-(2(8y+8)=0

We multiply parentheses

-1y+20y-(2(8y+8)+20=0

We add all the numbers together, and all the variables

19y-(2(8y+8)+20=0

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