-4(7z-12)=3z+62

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Solution for -4(7z-12)=3z+62 equation: 



-4(7z-12)=3z+62

We move all terms to the left:

-4(7z-12)-(3z+62)=0

We multiply parentheses

-28z-(3z+62)+48=0

We get rid of parentheses

-28z-3z-62+48=0

We add all the numbers together, and all the variables

-31z-14=0

We move all terms containing z to the left, all other terms to the right

-31z=14

z=14/-31

z=-14/31

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