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2/3x-1.5=6x-12
We move all terms to the left:
2/3x-1.5-(6x-12)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
2/3x-6x+12-1.5=0
We multiply all the terms by the denominator
-6x*3x+12*3x-(1.5)*3x+2=0
We multiply parentheses
-6x*3x+12*3x-4.5x+2=0
Wy multiply elements
-18x^2+36x-4.5x+2=0
We add all the numbers together, and all the variables
-18x^2+31.5x+2=0
a = -18; b = 31.5; c = +2;
Δ = b2-4ac
Δ = 31.52-4·(-18)·2
Δ = 1136.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31.5)-\sqrt{1136.25}}{2*-18}=\frac{-31.5-\sqrt{1136.25}}{-36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31.5)+\sqrt{1136.25}}{2*-18}=\frac{-31.5+\sqrt{1136.25}}{-36} $
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