4(2x-5)+2x=4(x-2)+3

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Solution for 4(2x-5)+2x=4(x-2)+3 equation: 



4(2x-5)+2x=4(x-2)+3

We move all terms to the left:

4(2x-5)+2x-(4(x-2)+3)=0

We add all the numbers together, and all the variables

2x+4(2x-5)-(4(x-2)+3)=0

We multiply parentheses

2x+8x-(4(x-2)+3)-20=0



We calculate terms in parentheses: -(4(x-2)+3), so:

4(x-2)+3

We multiply parentheses

4x-8+3

We add all the numbers together, and all the variables

4x-5

Back to the equation:

-(4x-5)



We add all the numbers together, and all the variables

10x-(4x-5)-20=0

We get rid of parentheses

10x-4x+5-20=0

We add all the numbers together, and all the variables

6x-15=0

We move all terms containing x to the left, all other terms to the right

6x=15

x=15/6

x=2+1/2

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