If it's not what You are looking for type in the equation solver your own equation and let us solve it.
/x-4=3x-3.5
We move all terms to the left:
/x-4-(3x-3.5)=0
Domain of the equation: x!=0We get rid of parentheses
x∈R
/x-3x+3.5-4=0
We multiply all the terms by the denominator
-3x*x+(3.5)*x-4*x+=0
We add all the numbers together, and all the variables
-4x-3x*x+(3.5)*x=0
We multiply parentheses
-4x-3x*x+3.5x=0
Wy multiply elements
-3x^2-4x+3.5x=0
We add all the numbers together, and all the variables
-3x^2-0.5x=0
a = -3; b = -0.5; c = 0;
Δ = b2-4ac
Δ = -0.52-4·(-3)·0
Δ = 0.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.5)-\sqrt{0.25}}{2*-3}=\frac{0.5-\sqrt{0.25}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.5)+\sqrt{0.25}}{2*-3}=\frac{0.5+\sqrt{0.25}}{-6} $
| 5w-8=12w+2 | | (2^x)*4^(x^2)=2 | | 7x-21=50 | | 2^x*4^(x^2)=2 | | x=x-150+x-250 | | (q-7)*2=48 | | 8=q-11 | | x=(x-150)+(x-250) | | 4(2x-5)+2x=4(x-2)+3 | | 9=10-y | | 4h+11=43 | | 2/3=3/r | | 7(x-2)-2x=6 | | 100^x*10^2x=4 | | 14x+49=2x+1 | | 2A+2b-2=0 | | ((x-4)/6)=-4 | | ((x-4)/6)=-6 | | ((x-3)/11)=8 | | 9-24u+6=1u+15 | | ((x-3)-11)=8 | | ((x-5)/3)=6 | | -1-5h=14h | | 6x+2=4x-14 | | (x/12)-9=-10 | | -3n-24=18 | | x2+7x-1=0 | | (x/5)-2=-9 | | x^+7x-1=0 | | (x/7)-5=-1 | | (x/8)+2=-4 | | 3(x+2)=7(x−6) |