2/3x+6=x+5

Solution for 2/3x+6=x+5 equation:

2/3x+6=x+5

We move all terms to the left:

2/3x+6-(x+5)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

2/3x-x-5+6=0

We multiply all the terms by the denominator


-x*3x-5*3x+6*3x+2=0

Wy multiply elements

-3x^2-15x+18x+2=0

We add all the numbers together, and all the variables

-3x^2+3x+2=0

a = -3; b = 3; c = +2;
Δ = b2-4ac
Δ = 32-4·(-3)·2
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{33}}{2*-3}=\frac{-3-\sqrt{33}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{33}}{2*-3}=\frac{-3+\sqrt{33}}{-6}
$