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7g-10=5+5/3g
We move all terms to the left:
7g-10-(5+5/3g)=0
Domain of the equation: 3g)!=0We add all the numbers together, and all the variables
g!=0/1
g!=0
g∈R
7g-(5/3g+5)-10=0
We get rid of parentheses
7g-5/3g-5-10=0
We multiply all the terms by the denominator
7g*3g-5*3g-10*3g-5=0
Wy multiply elements
21g^2-15g-30g-5=0
We add all the numbers together, and all the variables
21g^2-45g-5=0
a = 21; b = -45; c = -5;
Δ = b2-4ac
Δ = -452-4·21·(-5)
Δ = 2445
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{2445}}{2*21}=\frac{45-\sqrt{2445}}{42} $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{2445}}{2*21}=\frac{45+\sqrt{2445}}{42} $
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