20=10x-6(2x+50)

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Solution for 20=10x-6(2x+50) equation: 



20=10x-6(2x+50)

We move all terms to the left:

20-(10x-6(2x+50))=0



We calculate terms in parentheses: -(10x-6(2x+50)), so:

10x-6(2x+50)

We multiply parentheses

10x-12x-300

We add all the numbers together, and all the variables

-2x-300

Back to the equation:

-(-2x-300)



We get rid of parentheses

2x+300+20=0

We add all the numbers together, and all the variables

2x+320=0

We move all terms containing x to the left, all other terms to the right

2x=-320

x=-320/2

x=-160

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