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2/3x+10=5/9(x-9)
We move all terms to the left:
2/3x+10-(5/9(x-9))=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 9(x-9))!=0We calculate fractions
x∈R
(18xx/(27x^2x+(-(5*3x)/(27x^2x+10=0
We can not solve this equation
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