2/3c-3c+4=5/2c+7-3

Solution for 2/3c-3c+4=5/2c+7-3 equation:

2/3c-3c+4=5/2c+7-3

We move all terms to the left:

2/3c-3c+4-(5/2c+7-3)=0


Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R



Domain of the equation: 2c+7-3)!=0

We move all terms containing c to the left, all other terms to the right

2c-3)!=-7

c∈R


We add all the numbers together, and all the variables

2/3c-3c-(5/2c+4)+4=0

We add all the numbers together, and all the variables

-3c+2/3c-(5/2c+4)+4=0

We get rid of parentheses

-3c+2/3c-5/2c-4+4=0

We calculate fractions


-3c+4c/6c^2+(-15c)/6c^2-4+4=0

We add all the numbers together, and all the variables

-3c+4c/6c^2+(-15c)/6c^2=0

We multiply all the terms by the denominator


-3c*6c^2+4c+(-15c)=0

We add all the numbers together, and all the variables

4c-3c*6c^2+(-15c)=0

Wy multiply elements

-18c^3+4c+(-15c)=0

We get rid of parentheses

-18c^3+4c-15c=0

We do not support ecpression: c^3