7(4n+5)=2(7n+3)

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Solution for 7(4n+5)=2(7n+3) equation: 



7(4n+5)=2(7n+3)

We move all terms to the left:

7(4n+5)-(2(7n+3))=0

We multiply parentheses

28n-(2(7n+3))+35=0



We calculate terms in parentheses: -(2(7n+3)), so:

2(7n+3)

We multiply parentheses

14n+6

Back to the equation:

-(14n+6)



We get rid of parentheses

28n-14n-6+35=0

We add all the numbers together, and all the variables

14n+29=0

We move all terms containing n to the left, all other terms to the right

14n=-29

n=-29/14

n=-2+1/14

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