i=-i+(8-2i)-(5-9i)

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Solution for i=-i+(8-2i)-(5-9i) equation: 



i=-i+(8-2i)-(5-9i)

We move all terms to the left:

i-(-i+(8-2i)-(5-9i))=0

We add all the numbers together, and all the variables

i-(-i+(-2i+8)-(-9i+5))=0



We calculate terms in parentheses: -(-i+(-2i+8)-(-9i+5)), so:

-i+(-2i+8)-(-9i+5)

We add all the numbers together, and all the variables

-1i+(-2i+8)-(-9i+5)

We get rid of parentheses

-1i-2i+9i+8-5

We add all the numbers together, and all the variables

6i+3

Back to the equation:

-(6i+3)



We get rid of parentheses

i-6i-3=0

We add all the numbers together, and all the variables

-5i-3=0

We move all terms containing i to the left, all other terms to the right

-5i=3

i=3/-5

i=-3/5

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