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2/3-(k+1/4)=1/12(k+1)
We move all terms to the left:
2/3-(k+1/4)-(1/12(k+1))=0
Domain of the equation: 12(k+1))!=0We add all the numbers together, and all the variables
k∈R
-(+k+1/4)-(1/12(k+1))+2/3=0
We get rid of parentheses
-k-(1/12(k+1))-1/4+2/3=0
We calculate fractions
-k+()/(12(k+1))*4*3)+(-36kk/(12(k+1))*4*3)+(96kk/(12(k+1))*4*3)=0
We can not solve this equation
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