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8(c+2)-2(2c-2)=2(6c+5)
We move all terms to the left:
8(c+2)-2(2c-2)-(2(6c+5))=0
We multiply parentheses
8c-4c-(2(6c+5))+16+4=0
We calculate terms in parentheses: -(2(6c+5)), so:We add all the numbers together, and all the variables
2(6c+5)
We multiply parentheses
12c+10
Back to the equation:
-(12c+10)
4c-(12c+10)+20=0
We get rid of parentheses
4c-12c-10+20=0
We add all the numbers together, and all the variables
-8c+10=0
We move all terms containing c to the left, all other terms to the right
-8c=-10
c=-10/-8
c=1+1/4
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