20=4(u+1)+8

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Solution for 20=4(u+1)+8 equation: 



20=4(u+1)+8

We move all terms to the left:

20-(4(u+1)+8)=0



We calculate terms in parentheses: -(4(u+1)+8), so:

4(u+1)+8

We multiply parentheses

4u+4+8

We add all the numbers together, and all the variables

4u+12

Back to the equation:

-(4u+12)



We get rid of parentheses

-4u-12+20=0

We add all the numbers together, and all the variables

-4u+8=0

We move all terms containing u to the left, all other terms to the right

-4u=-8

u=-8/-4

u=+2

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