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2/3(x-4)=3/5(x-3)
We move all terms to the left:
2/3(x-4)-(3/5(x-3))=0
Domain of the equation: 3(x-4)!=0
x∈R
Domain of the equation: 5(x-3))!=0We calculate fractions
x∈R
(10xx/(3(x-4)*5(x-3)))+(-9xx/(3(x-4)*5(x-3)))=0
We calculate terms in parentheses: +(10xx/(3(x-4)*5(x-3))), so:
10xx/(3(x-4)*5(x-3))
We multiply all the terms by the denominator
10xx
Back to the equation:
+(10xx)
We calculate terms in parentheses: +(-9xx/(3(x-4)*5(x-3))), so:We get rid of parentheses
-9xx/(3(x-4)*5(x-3))
We multiply all the terms by the denominator
-9xx
Back to the equation:
+(-9xx)
10xx-9xx=0
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