(9x+3)/4=13-(2x-5)/5

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Solution for (9x+3)/4=13-(2x-5)/5 equation: 



(9x+3)/4=13-(2x-5)/5

We move all terms to the left:

(9x+3)/4-(13-(2x-5)/5)=0

We calculate fractions


9x/()+(-(13-(2x-5)*4)/()=0



We calculate terms in parentheses: +(-(13-(2x-5)*4)/(), so:

-(13-(2x-5)*4)/(

We multiply all the terms by the denominator


-(13-(2x-5)*4)



We calculate terms in parentheses: -(13-(2x-5)*4), so:

13-(2x-5)*4

determiningTheFunctionDomain
-(2x-5)*4+13

We multiply parentheses

-8x+20+13

We add all the numbers together, and all the variables

-8x+33

Back to the equation:

-(-8x+33)



We get rid of parentheses

8x-33

Back to the equation:

+(8x-33)



We get rid of parentheses

9x/()+8x-33=0

We multiply all the terms by the denominator


9x+8x*()-33*()=0

We add all the numbers together, and all the variables

9x+8x*()=0

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