4x+3(x-2)+5(x+2)=-20

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Solution for 4x+3(x-2)+5(x+2)=-20 equation:



4x+3(x-2)+5(x+2)=-20
We move all terms to the left:
4x+3(x-2)+5(x+2)-(-20)=0
We add all the numbers together, and all the variables
4x+3(x-2)+5(x+2)+20=0
We multiply parentheses
4x+3x+5x-6+10+20=0
We add all the numbers together, and all the variables
12x+24=0
We move all terms containing x to the left, all other terms to the right
12x=-24
x=-24/12
x=-2

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