2/3(9x-18)=4x+12

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Solution for 2/3(9x-18)=4x+12 equation: 



2/3(9x-18)=4x+12

We move all terms to the left:

2/3(9x-18)-(4x+12)=0



Domain of the equation: 3(9x-18)!=0

x∈R



We get rid of parentheses

2/3(9x-18)-4x-12=0

We multiply all the terms by the denominator


-4x*3(9x-18)-12*3(9x-18)+2=0

Wy multiply elements

-12x^2(9-36x(9+2=0

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