3(r+3)+3r=-4+5(r+1)

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Solution for 3(r+3)+3r=-4+5(r+1) equation: 



3(r+3)+3r=-4+5(r+1)

We move all terms to the left:

3(r+3)+3r-(-4+5(r+1))=0

We add all the numbers together, and all the variables

3r+3(r+3)-(-4+5(r+1))=0

We multiply parentheses

3r+3r-(-4+5(r+1))+9=0



We calculate terms in parentheses: -(-4+5(r+1)), so:

-4+5(r+1)

determiningTheFunctionDomain
5(r+1)-4

We multiply parentheses

5r+5-4

We add all the numbers together, and all the variables

5r+1

Back to the equation:

-(5r+1)



We add all the numbers together, and all the variables

6r-(5r+1)+9=0

We get rid of parentheses

6r-5r-1+9=0

We add all the numbers together, and all the variables

r+8=0

We move all terms containing r to the left, all other terms to the right

r=-8

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