-8(4x-6)-8(2x-5)=40

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Solution for -8(4x-6)-8(2x-5)=40 equation: 



-8(4x-6)-8(2x-5)=40

We move all terms to the left:

-8(4x-6)-8(2x-5)-(40)=0

We multiply parentheses

-32x-16x+48+40-40=0

We add all the numbers together, and all the variables

-48x+48=0

We move all terms containing x to the left, all other terms to the right

-48x=-48

x=-48/-48

x=1

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