2/3(6m-15)=1/2(12m+8)

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Solution for 2/3(6m-15)=1/2(12m+8) equation: 



2/3(6m-15)=1/2(12m+8)

We move all terms to the left:

2/3(6m-15)-(1/2(12m+8))=0



Domain of the equation: 3(6m-15)!=0

m∈R





Domain of the equation: 2(12m+8))!=0

m∈R



We calculate fractions


(4m1/(3(6m-15)*2(12m+8)))+(-3m6/(3(6m-15)*2(12m+8)))=0



We calculate terms in parentheses: +(4m1/(3(6m-15)*2(12m+8))), so:

4m1/(3(6m-15)*2(12m+8))

We multiply all the terms by the denominator


4m1

We add all the numbers together, and all the variables

4m

Back to the equation:

+(4m)





We calculate terms in parentheses: +(-3m6/(3(6m-15)*2(12m+8))), so:

-3m6/(3(6m-15)*2(12m+8))

We multiply all the terms by the denominator


-3m6

We add all the numbers together, and all the variables

-3m^6

We do not support empression: m^6

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