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2x+4(3-2x)=3(2x+2)/6+4
We move all terms to the left:
2x+4(3-2x)-(3(2x+2)/6+4)=0
We add all the numbers together, and all the variables
2x+4(-2x+3)-(3(2x+2)/6+4)=0
We multiply parentheses
2x-8x-(3(2x+2)/6+4)+12=0
We multiply all the terms by the denominator
2x*6+4)-8x*6+4)-(3(2x+2)+12*6+4)=0
We add all the numbers together, and all the variables
2x*6+4)-8x*6+4)-(3(2x=0
Wy multiply elements
12x+4)-8x*6+4)-(3(2x=0
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