1/2(z+5)=1/3(2z+10)

Solution for 1/2(z+5)=1/3(2z+10) equation:

1/2(z+5)=1/3(2z+10)

We move all terms to the left:

1/2(z+5)-(1/3(2z+10))=0


Domain of the equation: 2(z+5)!=0

z∈R



Domain of the equation: 3(2z+10))!=0

z∈R


We calculate fractions


(3z2/(2(z+5)*3(2z+10)))+(-2zz/(2(z+5)*3(2z+10)))=0


We calculate terms in parentheses: +(3z2/(2(z+5)*3(2z+10))), so:

3z2/(2(z+5)*3(2z+10))

We multiply all the terms by the denominator


3z2

We add all the numbers together, and all the variables

3z^2

Back to the equation:

+(3z^2)



We calculate terms in parentheses: +(-2zz/(2(z+5)*3(2z+10))), so:

-2zz/(2(z+5)*3(2z+10))

We multiply all the terms by the denominator


-2zz

Back to the equation:

+(-2zz)


We get rid of parentheses

3z^2-2zz=0