2/3(3x-1)+2=1/4(x+1)

Solution for 2/3(3x-1)+2=1/4(x+1) equation:

2/3(3x-1)+2=1/4(x+1)

We move all terms to the left:

2/3(3x-1)+2-(1/4(x+1))=0


Domain of the equation: 3(3x-1)!=0

x∈R



Domain of the equation: 4(x+1))!=0

x∈R


We calculate fractions


(8xx/(3(3x-1)*4(x+1)))+(-3x3/(3(3x-1)*4(x+1)))+2=0


We calculate terms in parentheses: +(8xx/(3(3x-1)*4(x+1))), so:

8xx/(3(3x-1)*4(x+1))

We multiply all the terms by the denominator


8xx

Back to the equation:

+(8xx)



We calculate terms in parentheses: +(-3x3/(3(3x-1)*4(x+1))), so:

-3x3/(3(3x-1)*4(x+1))

We multiply all the terms by the denominator


-3x3

We add all the numbers together, and all the variables

-3x^3

We do not support expression: x^3