(2x-1)+3(x-5)=-2(2x-1)

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Solution for (2x-1)+3(x-5)=-2(2x-1) equation:



(2x-1)+3(x-5)=-2(2x-1)
We move all terms to the left:
(2x-1)+3(x-5)-(-2(2x-1))=0
We multiply parentheses
(2x-1)+3x-(-2(2x-1))-15=0
We get rid of parentheses
2x+3x-(-2(2x-1))-1-15=0
We calculate terms in parentheses: -(-2(2x-1)), so:
-2(2x-1)
We multiply parentheses
-4x+2
Back to the equation:
-(-4x+2)
We add all the numbers together, and all the variables
5x-(-4x+2)-16=0
We get rid of parentheses
5x+4x-2-16=0
We add all the numbers together, and all the variables
9x-18=0
We move all terms containing x to the left, all other terms to the right
9x=18
x=18/9
x=2

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