3(3x-2)=7(4x+3-31x)

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Solution for 3(3x-2)=7(4x+3-31x) equation:



3(3x-2)=7(4x+3-31x)
We move all terms to the left:
3(3x-2)-(7(4x+3-31x))=0
We add all the numbers together, and all the variables
3(3x-2)-(7(-27x+3))=0
We multiply parentheses
9x-(7(-27x+3))-6=0
We calculate terms in parentheses: -(7(-27x+3)), so:
7(-27x+3)
We multiply parentheses
-189x+21
Back to the equation:
-(-189x+21)
We get rid of parentheses
9x+189x-21-6=0
We add all the numbers together, and all the variables
198x-27=0
We move all terms containing x to the left, all other terms to the right
198x=27
x=27/198
x=3/22

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