(3x-5)+(x+7)+(x+6)+x=(x+8)+(x+5)+(2x-1)

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Solution for (3x-5)+(x+7)+(x+6)+x=(x+8)+(x+5)+(2x-1) equation: 



(3x-5)+(x+7)+(x+6)+x=(x+8)+(x+5)+(2x-1)

We move all terms to the left:

(3x-5)+(x+7)+(x+6)+x-((x+8)+(x+5)+(2x-1))=0

We add all the numbers together, and all the variables

x+(3x-5)+(x+7)+(x+6)-((x+8)+(x+5)+(2x-1))=0

We get rid of parentheses

x+3x+x+x-((x+8)+(x+5)+(2x-1))-5+7+6=0



We calculate terms in parentheses: -((x+8)+(x+5)+(2x-1)), so:

(x+8)+(x+5)+(2x-1)

We get rid of parentheses

x+x+2x+8+5-1

We add all the numbers together, and all the variables

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

6x-(4x+12)+8=0

We get rid of parentheses

6x-4x-12+8=0

We add all the numbers together, and all the variables

2x-4=0

We move all terms containing x to the left, all other terms to the right

2x=4

x=4/2

x=2

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