2/3(2x+1)=5/6(3x-2)

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Solution for 2/3(2x+1)=5/6(3x-2) equation: 



2/3(2x+1)=5/6(3x-2)

We move all terms to the left:

2/3(2x+1)-(5/6(3x-2))=0



Domain of the equation: 3(2x+1)!=0

x∈R





Domain of the equation: 6(3x-2))!=0

x∈R



We calculate fractions


(12x3/(3(2x+1)*6(3x-2)))+(-15x2/(3(2x+1)*6(3x-2)))=0



We calculate terms in parentheses: +(12x3/(3(2x+1)*6(3x-2))), so:

12x3/(3(2x+1)*6(3x-2))

We multiply all the terms by the denominator


12x3

We add all the numbers together, and all the variables

12x^3

We do not support expression: x^3

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