12=-3(c-2)

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Solution for 12=-3(c-2) equation: 



12=-3(c-2)

We move all terms to the left:

12-(-3(c-2))=0



We calculate terms in parentheses: -(-3(c-2)), so:

-3(c-2)

We multiply parentheses

-3c+6

Back to the equation:

-(-3c+6)



We get rid of parentheses

3c-6+12=0

We add all the numbers together, and all the variables

3c+6=0

We move all terms containing c to the left, all other terms to the right

3c=-6

c=-6/3

c=-2

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