(3x+5)(3x+7)=6x+10

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Solution for (3x+5)(3x+7)=6x+10 equation: 



(3x+5)(3x+7)=6x+10

We move all terms to the left:

(3x+5)(3x+7)-(6x+10)=0

We get rid of parentheses

(3x+5)(3x+7)-6x-10=0

We multiply parentheses ..

(+9x^2+21x+15x+35)-6x-10=0

We get rid of parentheses

9x^2+21x+15x-6x+35-10=0

We add all the numbers together, and all the variables

9x^2+30x+25=0

a = 9; b = 30; c = +25;
Δ = b2-4ac
Δ = 302-4·9·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-30}{18}=-1+2/3$

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