2/(7x+3)=9/(2x-5)

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Solution for 2/(7x+3)=9/(2x-5) equation: 



2/(7x+3)=9/(2x-5)

We move all terms to the left:

2/(7x+3)-(9/(2x-5))=0



Domain of the equation: (7x+3)!=0

We move all terms containing x to the left, all other terms to the right

7x!=-3

x!=-3/7

x!=-3/7

x∈R





Domain of the equation: (2x-5))!=0

x∈R



We calculate fractions


4x/((7x+3)*(2x-5)))+(-(9*(7x+3))/((7x+3)*(2x-5)))=0



We calculate terms in parentheses: -(9*(7x+3))/((7x+3)*(2x-5))), so:

9*(7x+3))/((7x+3)*(2x-5))

We multiply all the terms by the denominator


9*(7x+3))

We multiply parentheses

63x+

We add all the numbers together, and all the variables

63x

Back to the equation:

-(63x)



We add all the numbers together, and all the variables

-63x+4x/((7x+3)*(2x-5)))+(=0

We multiply all the terms by the denominator


-63x*((7x+3)*(2x-5)))+(+4x=0

We add all the numbers together, and all the variables

4x-63x*((7x+3)*(2x-5)))+(=0

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