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2/(3x+10)=1/(x-1)
We move all terms to the left:
2/(3x+10)-(1/(x-1))=0
Domain of the equation: (3x+10)!=0
We move all terms containing x to the left, all other terms to the right
3x!=-10
x!=-10/3
x!=-3+1/3
x∈R
Domain of the equation: (x-1))!=0We calculate fractions
x∈R
2x/((3x+10)*(x-1)))+(-(1*(3x+10))/((3x+10)*(x-1)))=0
We calculate terms in parentheses: -(1*(3x+10))/((3x+10)*(x-1))), so:We multiply all the terms by the denominator
1*(3x+10))/((3x+10)*(x-1))
We multiply all the terms by the denominator
1*(3x+10))
Back to the equation:
-(1*(3x+10)))
2x-((1*(3x+10))))*((3x+10)*(x-1)))+(=0
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