10(5+c)=8(c-3)

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Solution for 10(5+c)=8(c-3) equation: 



10(5+c)=8(c-3)

We move all terms to the left:

10(5+c)-(8(c-3))=0

We add all the numbers together, and all the variables

10(c+5)-(8(c-3))=0

We multiply parentheses

10c-(8(c-3))+50=0



We calculate terms in parentheses: -(8(c-3)), so:

8(c-3)

We multiply parentheses

8c-24

Back to the equation:

-(8c-24)



We get rid of parentheses

10c-8c+24+50=0

We add all the numbers together, and all the variables

2c+74=0

We move all terms containing c to the left, all other terms to the right

2c=-74

c=-74/2

c=-37

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